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试卷2

数学

单选题 (共 6 题 ),每题只有一个选项正确
$n$ 维向量组 ${\alpha}_{1}, {\alpha}_{2}, \cdots, {\alpha}_{s}(3 \leqslant s \leqslant n)$ 线性无关的充分必要条件是 (  )
$\text{A.}$ 存在一组不全为零的数 $k_{1}, k_{2}, \cdots, k_{s}$, 使 $k_{1} {\alpha}_{1}+k_{2} {\alpha}_{2}+\cdots+k_{s} {\alpha}_{s} \neq \mathbf{0}$. $\text{B.}$ ${\alpha}_{1}, {\alpha}_{2}, \cdots, {\alpha}_{s}$ 中任意两个向量都线性无关. $\text{C.}$ ${\alpha}_{1}, {\alpha}_{2}, \cdots, {\alpha}_{s}$ 中存在一个向量,它不能用其余向量线性表出. $\text{D.}$ ${\alpha}_{1}, {\alpha}_{2}, \cdots, {\alpha}_{s}$ 中任意一个向量都不能用其余向量线性表出.

已知向量组 $\boldsymbol{\alpha}_{1}, \boldsymbol{\alpha}_{2}, \boldsymbol{\alpha}_{3}, \boldsymbol{\alpha}_{4}$ 线性无关, 则向量组
$\text{A.}$ $ {\alpha}_{1}+ {\alpha}_{2}, {\alpha}_{2}+ {\alpha}_{3}, {\alpha}_{3}+ {\alpha}_{4}, {\alpha}_{4}+ {\alpha}_{1}$ 线性无关. $\text{B.}$ $ {\alpha}_{1}- {\alpha}_{2}, {\alpha}_{2}- {\alpha}_{3}, {\alpha}_{3}- {\alpha}_{4}, {\alpha}_{4}- {\alpha}_{1}$ 线性无关. $\text{C.}$ $ {\alpha}_{1}+ {\alpha}_{2}, {\alpha}_{2}+ {\alpha}_{3}, {\alpha}_{3}+ {\alpha}_{4}, {\alpha}_{4}- {\alpha}_{1}$ 线性无关. $\text{D.}$ $ {\alpha}_{1}+ {\alpha}_{2}, {\alpha}_{2}+ {\alpha}_{3}, {\alpha}_{3}- {\alpha}_{4}, {\alpha}_{4}- {\alpha}_{1}$ 线性无关.

向量组 $\alpha_1, \alpha_2 \cdots, \alpha_s$ 线性无关的充分条件是
$\text{A.}$ $\alpha_1, \alpha_2 \cdots, \alpha_s$ 均不为零向量 $\text{B.}$ $\alpha_1, \alpha_2 \cdots, \alpha_s$ 中任意两个向量的分量不成比例 $\text{C.}$ $\alpha_1, \alpha_2 \cdots, \alpha_s$ 中任意一个向量均不能由其余 $s-1$ 个向量线性表示 $\text{D.}$ $\alpha_1, \alpha_2 \cdots, \alpha_s$ 中有一部分向量线性无关

设 $\alpha_1, \alpha_2, \cdots, \alpha_m$ 均为 $n$ 维向量,那么下列结论正确的是
$\text{A.}$ 若 $k_1 \alpha_1+k_2 \alpha_2+\cdots+k_m \alpha_m=0$ ,则 $\alpha_1, \alpha_2, \cdots, \alpha_m$线性相关 $\text{B.}$ 若对任意一组不全为零的数 $k_1, k_2, \cdots, k_m$ ,都有$k_1 \alpha_1+k_2 \alpha_2+\cdots+k_m \alpha_m \neq 0 \text { , }$ 则 $\alpha_1, \alpha_2, \cdots, \alpha_m$ 线性无关 $\text{C.}$ 若 $\alpha_1, \alpha_2, \cdots, \alpha_m$ 线性相关,则对任意一组不全为零的数 $k_1, k_2, \cdots, k_m$ ,都有 $k_1 \alpha_1+k_2 \alpha_2+\cdots+k_m \alpha_m=0$ $\text{D.}$ 若 $0 \alpha_1+0 \alpha_2+\ldots+0 \alpha_m=0$ ,则 $\alpha_1, \alpha_2, \cdots, \alpha_m$ 线性无关

设向量组 $\alpha_1=(1,-1,2,4), \alpha_2=(0,3,1,2), \alpha_3=(3,0,7,14)$, $\alpha_4=(1,-2,2,4), \alpha_5=(2,1,5,10)$ ,则该向量组的极大线性无关组是
$\text{A.}$ $\alpha_1, \alpha_2, \alpha_3$ $\text{B.}$ $\alpha_1, \alpha_2, \alpha_4$ $\text{C.}$ $\alpha_1, \alpha_2, \alpha_5$ $\text{D.}$ $\alpha_1, \alpha_2, \alpha_4, \alpha_5$

设 $n$ 维行向量 $\alpha=\left(\frac{1}{2}, 0 \cdots, 0 \frac{1}{2}\right)$ ,矩阵 $A=E-\alpha^T \alpha, B=E+2 \alpha^T \alpha,$ 其中 $E$ 为 $n$ 阶单位矩阵,则 $A B$ 等于
$\text{A.}$ 0 $\text{B.}$ $-{E}$ $\text{C.}$ $E$ $\text{D.}$ $E+\alpha^T \alpha$

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