• 试题 ID 12371


若 $\alpha \in\left(\frac{\pi}{4}, \frac{3 \pi}{4}\right), 6 \tan \left(\frac{\pi}{4}+\alpha\right)+4 \cos \left(\frac{\pi}{4}-\alpha\right)=5 \cos 2 \alpha$, 则 $\sin 2 \alpha=$
A $\frac{24}{25}$
B $\frac{12}{25}$
C $\frac{7}{25}$
D $\frac{1}{5}$
E
F
答案:

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解析:

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