• 试题 ID 5361


计算
(1)$
\left|\begin{array}{lll}
2 & 5 & 4 \\
3 & 1 & 2 \\
5 & 4 & 6
\end{array}\right|
$

(2)$\left|\begin{array}{rrrr}
2 & 0 & 0 & 1 \\
0 & 1 & 0 & 0 \\
1 & 6 & 2 & 0 \\
1 & 1 & -2 & 3
\end{array}\right| .$
A
B
C
D
E
F
答案:

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解析:

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