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试题 ID 9271
【所属试卷】
重庆一外2023学年初二上数学第一次月考
解不等式组:
(1) $\left\{\begin{array}{l}5 x-2>3(x-1) \\ x-2 \leq 14-3 x\end{array}\right.$;
(2) $\left\{\begin{array}{l}2(x-1)-x < 1 \\ \frac{x+2}{2} \geq \frac{2 x-1}{3}+1\end{array}\right.$.
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答案：
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解析：
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解不等式组:<br>(1) $\left\{\begin{array}{l}5 x-2>3(x-1) \\ x-2 \leq 14-3 x\end{array}\right.$;<br><br>(2) $\left\{\begin{array}{l}2(x-1)-x < 1 \\ \frac{x+2}{2} \geq \frac{2 x-1}{3}+1\end{array}\right.$. <div> </div> <br /> <br /> <b>答案</b> <div> 答案与解析仅限VIP可见 </div> <br /> <br /> <b>解析</b> <div> 答案与解析仅限VIP可见 </div>