• 试题 ID 9911


矩阵 $\boldsymbol{A}=\left[\begin{array}{cc}1 & -1 \\ -1 & 1\end{array}\right]$,与 $\boldsymbol{A}$ 合同但不相似的矩阵为
A $\left[\begin{array}{ll}1 & 1 \\ 1 & 1\end{array}\right]$.
B $\left[\begin{array}{ll}2 & 0 \\ 0 & 0\end{array}\right]$.
C $\left[\begin{array}{ll}3 & 0 \\ 0 & 0\end{array}\right]$.
D $\left[\begin{array}{ll}-1 & -1 \\ -1 & -1\end{array}\right]$.
E
F
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