单选题 （共 3 题 ），每题只有一个选项正确
设 $f(x, y)$ 在点 $P_0\left(x_0, y_0\right)$ 处有二阶连续偏导数, 且 $f(x, y)$ 在 $P_0$ 处取得极大 值, 则
$\text{A.}$ $f_{x x}^{\prime \prime}\left(P_0\right) \geqslant 0, f_{y y}^{\prime \prime}\left(P_0\right) \geqslant 0$.
$\text{B.}$ $f_{x x}^{\prime \prime}\left(P_0\right) < 0, f_{y y}^{\prime \prime}\left(P_0\right) < 0$.
$\text{C.}$ $f_{x x}^{\prime \prime}\left(P_0\right) \leqslant 0, f_{y y}^{\prime \prime}\left(P_0\right) \leqslant 0$.
$\text{D.}$ $f_{x x}^{\prime \prime}\left(P_0\right) \leqslant 0, f_{y y}^{\prime \prime}\left(P_0\right) \geqslant 0$.
设 $z=\sin \left(x+y^2\right)$ ，则 $\dfrac{\partial^2 z}{\partial x^2}=$.
$\text{A.}$ $-\sin \left(x+y^2\right)$
$\text{B.}$ $-\cos \left(x+y^2\right)$
$\text{C.}$ $\sin \left(x+y^2\right)$
$\text{D.}$ $\cos \left(x+y^2\right)$
设 $f(x, y)=\left\{\begin{array}{ll}\left(x^2+y^2\right) \cos \left(\frac{1}{\sqrt{x^2+y^2}}\right), & x^2+y^2 \neq 0, \\ 0, & x^2+y^2=0,\end{array}\right.$ 则 $f(x, y)$ 在点 $(0,0)$ 处
$\text{A.}$ $\frac{\partial f}{\partial x}, \frac{\partial f}{\partial y}$ 不存在
$\text{B.}$ $\frac{\partial f}{\partial x}, \frac{\partial f}{\partial y}$ 连续
$\text{C.}$ 可微
$\text{D.}$ 不连续
填空题 （共 3 题 ），请把答案直接填写在答题纸上
设向量场 $\boldsymbol{A}(x, y, z)=x y \boldsymbol{i}-y z \boldsymbol{j}+z x \boldsymbol{k}$, 则 $\operatorname{div}[\operatorname{rot} \boldsymbol{A}(x, y, z)]=$
设 $z=z(x, y)$ 由方程组 $\left\{\begin{array}{l}x=(t+1) \cos z, \\ y=t \sin z\end{array}\right.$ 确定, $t=t(x, y)$, 则 $\frac{\partial z}{\partial x}=$
设 $z=\frac{1}{x} f\left(x^2 y\right)+x y g(x+y)$ ，其中 $f, g$ 具有二阶连续导数， 计算 $\frac{\partial^2 z}{\partial x^2}, \frac{\partial^2 z}{\partial x \partial y}$.